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Template std.traits.hasElaborateDestructor
True if S
or any type directly embedded in the representation
of S
defines an elaborate destructor. Elaborate destructors
are introduced by defining ~this()
for a struct
.
Classes and unions never have elaborate destructors, even
though classes may define ~this()
.
Arguments
template hasElaborateDestructor(S);
Example
static assert(!hasElaborateDestructor!int); static struct S1 { } static struct S2 { ~this() {} } static struct S3 { S2 field; } static struct S4 { S3[1] field; } static struct S5 { S3[] field; } static struct S6 { S3[0] field; } static struct S7 { @disable this(); S3 field; } static assert(!hasElaborateDestructor!S1); static assert( hasElaborateDestructor!S2); static assert( hasElaborateDestructor!(immutable S2)); static assert( hasElaborateDestructor!S3); static assert( hasElaborateDestructor!(S3[1])); static assert(!hasElaborateDestructor!(S3[0])); static assert( hasElaborateDestructor!S4); static assert(!hasElaborateDestructor!S5); static assert(!hasElaborateDestructor!S6); static assert( hasElaborateDestructor!S7);
Authors
Walter Bright,
Tomasz Stachowiak (
),
Andrei Alexandrescu,
Shin Fujishiro,
Robert Clipsham,
David Nadlinger,
Kenji Hara,
Shoichi Kato
isExpressions